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onclick="setCopy('http://forum.oecr.com/plugin.php?id=attachcenter:page&aid=39931', '链接已经复制到剪贴板');" type="submit"> <em>复制链接推荐给好友</em></button> <input type="text" class="px vm" onclick="this.select();setCopy(this.value, '链接已经复制到剪贴板');" value="http://forum.oecr.com/plugin.php?id=attachcenter:page&aid=39931" size="50" /></p> </div> <div class="bm"> <div class="bm_c xld"> <b>(原创)小半径标准样板检定问题:</b><div class="postmsg">小半径标准样板检定时要注意的问题<br /> 08年5月红外目镜中有一个半径13.305半径的透镜要急做，由于制作超半球标准样板（还叫对板或原器）周期长，就直接开直径ф20mm标准样板，并做了各工序用的工作样板。标准样板送计量检定时问题来啦，用公式 ……（ 1）计算半径值是13.302mm，这是迭代2次的结果。我们厂历来只生产A类标准样板，也就是13.305 mm的误差是2μm，下限是13.303 mm，现在13.302mm不合格。光学分厂技术员过来，说他们是按照球经仪的指标进行工艺安排，这台苏联球经仪的第7号圈口半径r=7.4842mm；钢珠半径ρ=1.272mm；半径13.305mm的标准样板2倍失高2h是按下 ……（2）式计算的，计算结果：2h=4.6787。我把4.6787代入（1）式，结果是13.302mm，和我实测值一样，问题一定出现在计算公式上。<br /> 终于查到问题出在 公式，北理工“光学测量与像质检定”第219页指出：<br /> <br /> 令 ……（3）<br /> 则 <br /> 求 时将（3）式两边平方，得： <br /> 因ρ比R和r小得多，故可略去ρ4项，则<br /> <br /> 上式右边带根号一项，采用二项式定理展开，仅取头两项得：<br /> <br /> 则得： <br /> 简化后得： ，<br /> 上式右边用二项式定理展开，仅取头两项得：<br /> <br /> 由以上可见，ρ4略去，两次展开仅取前两项，使 是一个近似值，只有当R比ρ大很多时才准确，故国标将35毫米以下做成半球是有道理的，用测长仪就避开了用球径仪时公式近似的影响。<br /> 复制后好像没有公式发附件如下</div> <div class="postmsg">目的是提醒做手机数码的朋友，标准样板要做超半球，接受检定半径35mm以下标准样板时，如果不是半球应当用激光球面干涉仪测半径。</div> <div class="postmsg"><i class="pstatus"> 本帖最后由 bhutl 于 2014-5-15 14:12 编辑 </i><br /> <br /> 高<br /> <br /> <br /> </div> <div style="height200px;"></div> <ul class="xl xl2 cl" style="border-top: 1px #cccccc dashed;margin:5px 0 ;padding-top:5px"> <dl><b> 同一主题资料:</b></dl><dl class='icon'><img src="static/image/filetype/msoffice.gif" border="0" class="vm" alt="" /> <a href="attachcenter-page.html?aid=39931" title="小半径标准样板检定问题.doc">小半径标准样板检定问题.doc</a> <font color="#AAAAAA">(50 KB)</font> </dl> <dl style="margin:10px 1px;display:inline"><a href="attachcenter-page.html?aid=85953" title="1.JPG"><img src="data/attachment/forum/201405/15/140539gx3um7jfxfxgea79.jpg" alt="1.JPG" title="1.JPG" onload="javascript:if(this.width>130)this.width=130;"></a></dl> </div> 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