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class="postmsg">是楼主出的简单还是我不明白？<br /> 波长0.65*1.33 um，颜色不变<br /> 高中物理<br /> <br /> [<i> 本帖最后由 liuqianblue 于 2008-8-6 22:31 编辑 </i>]</div> <div class="postmsg">0.8645um吧，红光，光束的波长和速度是和介质有关的。</div> <div class="postmsg">0.65/1.33=0.488微米 黄光 不知道我算得对不对，楼主给一下答案</div> <div class="postmsg">真晕了 光的频率是固定的 波长怎么会变呢 折射率改变速度会改变，颜色也不变</div> <div class="postmsg">答案到底是啥呢？我认为波长也不会改变的呀</div> <div class="postmsg">频率不变，所以颜色不变，波长变长</div> <div class="postmsg">我来回答。<br /> 光的颜色是和它的频率相关的。频率是一个定值，不因别的条件改变而改变。所以水中光的颜色不变，仍为红色<br /> 波长变化了。因为波长等于速度除以频率。光在水中的速度可以算出来。频率也有了。所以波长也有了<br /> 这里可以看出大家的基础知识掌握的很不牢固。大家真的应该好好看看基础去了</div> <div class="postmsg">呵呵！这个问题看起来确实很简单，但是深究起来确并不简单！说它简单是因为我们知道以光程计算的光速是常数c，由此容易推出在空气中650nm波长的红光在水中的波长将变成650nm/1.33＝489nm，属于440nm－500nm之间的蓝光波段，由此推出在空气中650nm波长的红光在水中的颜色应该为蓝色。但深究一下就知道我们犯了一个严重的错误，我们眼镜里的视网膜和视觉神经都不是裸露在空气中的，它们在我们体内的液体环境中，而且这个环境从光学上讲其折射率应该是一个相对固定的值，所以不管是什么光，只要是其频率不变，不管其在外界的多少种介质中波长如何变化，最终进入人眼后其波长都不会改变，即光的颜色决定于其频率而不是波长。由此可知在空气中650nm波长的红光不但在水中还是红光，到任何其他的透光介质中也都还是红光。</div> <div class="postmsg">ls的概念不对吧，颜色由频率决定而不是由波长决定吧<br /> 频率不变，颜色当然不变吧<br /> 但是折射率变了，当然波长要变了，因为折射率等于不同介质中光速的比值嘛</div> <div class="postmsg">顶13楼的 <br /> <img src="static/image/smiley/default/em17.gif" smilieid="46" border="0" alt="" /> <img src="static/image/smiley/default/em17.gif" smilieid="46" border="0" alt="" /> <img src="static/image/smiley/default/em17.gif" smilieid="46" border="0" alt="" /></div> <div class="postmsg">我就有个毛病 遇到什么问题总是喜欢去问别人 让别人告诉我<br /> 我觉得这样不好<br /> 要自己去找资料 自己刻意的培养自己自学的能力<br /> <br /> 这点国外的一些国家的教学就体现的非常好</div> <div class="postmsg">什么什么啊？？？波长会变么？变的是光的传播速度而已啊~~~光的波长怎么会因为传播介质而改变呢？频率没变波长肯定也没变啊~~~</div> <div class="postmsg">翻页ING。。。。。<img src="static/image/smiley/default/em49.gif" smilieid="78" border="0" alt="" /> <img src="static/image/smiley/default/em49.gif" smilieid="78" border="0" alt="" /> <img src="static/image/smiley/default/em49.gif" smilieid="78" border="0" alt="" /></div> <div class="postmsg"><div class="quote"><blockquote>原帖由 <i>qyxhhl</i> 于 2008-10-8 20:44 发表 <a href="http://bbs.oecr.com/redirect.php?goto=findpost&pid=485887&ptid=72942" target="_blank"><img id="aimg_CY79W" onclick="zoom(this, this.src, 0, 0, 0)" class="zoom" src="static/image/common/back.gif" onmouseover="img_onmouseoverfunc(this)" onload="thumbImg(this)" border="0" alt="" /></a><br /> 什么什么啊？？？波长会变么？变的是光的传播速度而已啊~~~光的波长怎么会因为传播介质而改变呢？频率没变波长肯定也没变啊~~~ </blockquote></div><br /> <br /> <br /> 呵呵！还是您厉害！频率和波长都不变的情况下速度还会自己变！强人呀！呵呵</div> <div class="postmsg">我说的速度是光在介质中的传播速度，比如在真空中是C，到了空气中比C要小些，难道波长就变了？莫名其妙。。。搞的像你很牛一样~~~~波长和频率是波自己的特性~~~~公式n=c/v不就说明了这个问题嘛~~~本来速度是c到了另一个介质中变成了速度v~~~~好像不关波长的事吧？<br /> <br /> [<i> 本帖最后由 qyxhhl 于 2008-10-9 12:06 编辑 </i>]</div> <div class="postmsg">不用争了,楼主题目出的就有问题.<br /> 光的颜色只和频率有关,频率是固定的,颜色就不会变.<br /> 楼上的,你学过物理光学没?</div> <div class="postmsg">呵呵！楼上的说的很对，他不但没学过物理学，我看他就连数学也没学过！呵呵</div> <div class="postmsg">你学的那么好那你说我说的哪儿不对啊?</div> <div class="postmsg">频率：只取决于波源，而与速度和波长无关；<br /> 波速决定于介质的物理性质，它与周期和波长无关。<br /> 波长则决定于速度和频率 ，只要其中一个发生变化，<br /> 波长必然发生变化，而保持速度=波长乘以频率的关系.</div> <div class="postmsg">又重新看了下书~~~~太丢人了。。。。唉，多谢了~~~又多学了点知识~~~<img src="static/image/smiley/default/em17.gif" smilieid="46" border="0" alt="" /></div> <div class="postmsg"><div class="quote"><blockquote>原帖由 <i>litwei</i> 于 2008-10-9 13:02 发表 <a href="http://bbs.oecr.com/redirect.php?goto=findpost&pid=486020&ptid=72942" target="_blank"><img id="aimg_B364G" onclick="zoom(this, this.src, 0, 0, 0)" class="zoom" src="static/image/common/back.gif" onmouseover="img_onmouseoverfunc(this)" onload="thumbImg(this)" border="0" alt="" /></a><br /> 不用争了,楼主题目出的就有问题.<br /> 光的颜色只和频率有关,频率是固定的,颜色就不会变.<br /> 楼上的,你学过物理光学没? </blockquote></div><br /> <br /> <br /> 题目没问题！！！！！！！！！！！！！！！！！！<br /> <br /> 答案自己去书上找！！！！！！！！！！！！！！！<br /> <br /> <img src="static/image/smiley/default/funk.gif" smilieid="29" border="0" alt="" /></div> <div class="postmsg">恩,题目的确没问题,题太简单反而容易让人误解.<br /> 现在把答案发上来.</div> <div class="postmsg">该回复比较专业！<img src="static/image/smiley/default/em44.gif" smilieid="73" border="0" alt="" /> <br /> 不明白的再研究下了。</div> <div class="postmsg">题目出得没有问题，不过很多人的回答让人哭笑不得啊</div> <div class="postmsg">果然我又想错了，谢谢会的人指导</div> <div class="postmsg">哈哈...大家是要多看看基础了、、、</div> <div class="postmsg">13楼的是牛人啊<br /> 光速肯定变，频率不变，波长自然变，颜色和频率还是波长有关暂时还搞不懂</div> <div class="postmsg">我虽然知道答案，但不能想楼主那样解释这么清楚。又学到东西了</div> <div class="postmsg">11楼正解~19楼没学过物理不要乱说话~</div> <div class="postmsg">不清楚有些人到底学过光学没有，学过一点数学没有。</div> <div class="postmsg">速度等于传播周期和频率的乘积<br /> 这个周期对光来也就是波长<br /> 速度变了<br /> 频率没变 <br /> 那就是波长变了<br /> <br /> 颜色不变是真的<br /> 首先颜色是频率决定的 <br /> 还可以换个角度考虑<br /> 也就是13楼高人说的<br /> 很经典的 那就是光进水再反射回来我们才能看见<br /> 也就是说到我们眼睛中的光和入射的光根据可逆原理 都是一样的<br /> 当然颜色不变的了<br /> 呵呵<br /> <br /> 就像那个航天员的笔一样 换个角度想的话不可思议<br /> 但是符合要求 <br /> 还简单的要死 出乎意料<br /> 呵呵</div> <div class="postmsg">刚才看了下答案<br /> 突然记得好像以前学基础物理的时候光学部分涉及到这点的时候说的是比例关系<br /> 也就是说介质的折射率比等于波长的反比<br /> 换算成成绩的关系得到的是守恒量<br /> 形式上和飞成像光学中的光学扩展量有点相似<br /> 那位高人给解释下<br /> 是不是一样的关系呢<br /> 波长和折射率是反比关系 等效化为速度也是反比关系的<br /> 谢谢先</div> <div class="postmsg"><div class="quote"><blockquote>原帖由 <i>qyxhhl</i> 于 2008-10-8 20:44 发表 <a href="http://bbs.oecr.com/redirect.php?goto=findpost&pid=485887&ptid=72942" target="_blank"><img id="aimg_l7X7H" onclick="zoom(this, this.src, 0, 0, 0)" class="zoom" src="static/image/common/back.gif" onmouseover="img_onmouseoverfunc(this)" onload="thumbImg(this)" border="0" alt="" /></a><br /> 什么什么啊？？？波长会变么？变的是光的传播速度而已啊~~~光的波长怎么会因为传播介质而改变呢？频率没变波长肯定也没变啊~~~ </blockquote></div><br /> <br /> <br /> <br /> 频率没变，波长等于光速除以频率，光速变了，你说波长变了没？</div> <div style="height200px;"></div> <ul class="xl xl2 cl" style="border-top: 1px #cccccc dashed;margin:5px 0 ;padding-top:5px"> <dl><b> 同一主题资料:</b></dl><dl class='icon'><img src="static/image/filetype/msoffice.gif" border="0" class="vm" alt="" /> <a href="attachcenter-page.html?aid=31337" title="波长.doc">波长.doc</a> <font color="#AAAAAA">(103 KB)</font> </dl> <dl class='icon'><img src="static/image/filetype/msoffice.gif" border="0" class="vm" alt="" /> <a 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