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title="光学仪器设计手册 上册 （光学设计与光学测量）_10127417.part8.rar">光学仪器设计手册 上册 （光学设计与光学测量）_10127417.part8.rar</a></li> </ul> </div> </div> <div class="bm"> <div class="bm_c" style=" FONT: 11px Verdana"> </div> </div> </div> <div class="showatt_right"> <div class="bm"> <div class="bm_h cl"> <a href="#" class="y xi2 xw1"></a> <h1 class="xs2 icon"><img src="static/image/filetype/text.gif" border="0" class="vm" alt="" /> 初步乱算.txt</h1> </div> <div class="bm_c xld"> <div class="attbox_right_ad"> </div> <div class="attbox_left"> <ul> <li>打开方式: 记事本</li> <li>资料大小: 17.63 KB</li> <li>下载次数: 22</li> <li>上传会员: <a href="attachcenter-list.html?uid=55988" target="_blank" style="color:#FF9900">guogg119</a></li> <li>上传时间: 2008-04-18</li> <li>本站网址: <a href="http://forum.oecr.com/">forum.oecr.com</a></li> <li><a href="http://bbs.oecr.com/thread-68795-1-1.html" target="_blank">查看资料所在的主题</a></li> <li><a href="http://bbs.oecr.com/forum.php?mod=attachment&aid=MjYxMTF8NjYwMDJjMmZ8MTc2NjUxNDgxOHwwfDA%3D" target="_blank" style="color:#FF9900">下载资料 </a></li> </ul> </div> <DIV style="CLEAR: both"></DIV> <b>欢迎下载本站资料，下载前请先登录您的社区账号。</b></div> </div> <DIV style="CLEAR: both"></DIV> <div class="bm cl" style="padding:5px;"> <p><button type="submit" class="pn vm" onclick="setCopy('http://forum.oecr.com/plugin.php?id=attachcenter:page&aid=26111', '链接已经复制到剪贴板');" type="submit"> <em>复制链接推荐给好友</em></button> <input type="text" class="px vm" onclick="this.select();setCopy(this.value, '链接已经复制到剪贴板');" value="http://forum.oecr.com/plugin.php?id=attachcenter:page&aid=26111" size="50" /></p> </div> <div class="bm"> <div class="bm_c xld"> <b>求助公差问题:</b><div class="postmsg"><br /> <br /> 刚刚接触公差，有很多不懂的地方，希望高手解答一下。谢谢。<br /> 下面是我随便算的，不是太懂。<br /> Criteria : Geometric MTF average S&T at 20.0000 lp/mm<br /> Mode : Inverse Sensitivities, Limit Criteria Value : 0.70000000<br /> Sampling : 5<br /> Nominal Criteria : 0.82512142<br /> Test Wavelength : 0.5500<br /> Nominal Criteria 是什么意思？这个值是我设计的这个镜头在20线对时的mtf值呀。<br /> 不是说在光学设计中给所有工艺允许的总公差是： 使最差情况下的传函由于工艺因素的总下降量不大于0.15 lp/mm嘛。这个怎么体现呢？<br /> 是在Limit Criteria Value 这里么？是不是应该等于Nominal Criteria减去0.15lp/mm呢？？<br /> 请高手请解一下，在线等。。。。。。。。。<br /> <br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <br /> Nominal Criteria 是名义值，即理想情况下的对应空间频率的MTF值，<br /> <br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <div class="quote"><blockquote>原帖由 <i>guogg119</i> 于 2008-4-18 15:53 发表 =http://bbs.oecr.com/redirect.php?goto=findpost&pid=445116&ptid=68795]static/image/common/back.gif<br /> 刚刚接触公差，有很多不懂的地方，希望高手解答一下。谢谢。<br /> 下面是我随便算的，不是太懂。<br /> Criteria : Geometric MTF average S&T at 20.0000 lp/mm<br /> Mode : Inverse Sensitivities, ... </blockquote></div><br /> 不晓得您明白了没，我的问题现在是这个列子中，如何去收紧或放松公差？请告知<br /> <br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <br /> Mode: Inverse Sensitivities, Limit Criteria Value : 0.70000000<br /> 如果某项公差太松，Zemax 将计算使 MFT 降到0.7时的值。<br /> 再看看 Worst Offenders, 至少你给的公差中最松的十项都使系统的 MTF 下降到0.7以下。你应收紧这些公差，再算，直到满意为止。<br /> Worst offenders:<br /> Type Value Criteria Change<br /> TTHI 10 11 -0.123188405 0.699999747 -0.125121673<br /> TSTX 11 -0.025176487 0.699999824 -0.125121596<br /> TSTX 11 0.025176487 0.699999824 -0.125121596<br /> TTHI 10 11 0.119277015 0.699999858 -0.125121562<br /> TETX 12 13 -0.014598614 0.699999947 -0.125121473<br /> TETX 12 13 0.014598614 0.699999947 -0.125121473<br /> TTHI 9 11 0.142646778 0.699999963 -0.125121457<br /> TTHI 11 13 0.144787191 0.699999964 -0.125121456<br /> TTHI 11 13 -0.136892935 0.699999974 -0.125121446<br /> TTHI 9 11 -0.172297905 0.699999976 -0.125121444<br /> <br /> <br /> <br /> <br /> </div> <div style="height200px;"></div> </div> </div> </div> </div></div> </div> <!--autocomment filter by maxnum--> <div class="ft_wp"> <div id="ft" class=" cl"> <div id="flk" > <p> <a href="http://wpa.qq.com/msgrd?V=3&Uin=20600600&Site=光电工程师社区&Menu=yes&from=discuz" target="_blank" title="QQ"><img src="static/image/common/site_qq.jpg" 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