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经过一个多月的努力，将在讯技公司“数码镜头设计原理”专题讲座的讲稿全部完成并发出。内中有超大口径，超大视场数码镜头设计：利用Zemax构建理想光组模型，在Mathematica上编写完WPC一系列专用算式组，能自动创建WPC平衡方程组，能自动解出各镜的WPC，并根据WPC值自动解出单镜和双胶合镜的初始结构。我用此组公式设计出了2W=120°，F#=1.2的数码镜头，0.7视场以内传函为95 lp/mm，全视场也有35 lp/mm（见附件），全文详细记录了设计的全过程。<br /> 由于时间太紧，在不到一星期时间，连推公式，写这章讲稿，带设计这个镜头。因此只完成了象差自动校正。间隔，材料都没纳入校正，畸变也很大。也没用上锤形优化。最主要的没用上传函自动校正（只用了以象差为象质评价函数的全局优化）。如果这些办法都用上，最终结果一定是会令人满意的。<br /> 这次能如此顺利的解决这个难题，我也出乎意料。这完全得益于Mathematica软件超凡脱俗的功能，真诚希望光学同行尽快掌握它。<br /> 本例只是WPC法应用一列，它可用于各种场合。如手机、变焦、特种用途的监视镜头的设计上。WPC法是光学理论，数学计算方法的综合应用，是光学设计从背动（仿型设计）到主动（全自主设计）的必由之路。是对从事光学设计人员能力的挑战，我们只要契而不舍的努力钻研，是一定可以掌握它的。<br /> GGX19458132 2005.3.2</P><br /> <br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <br /> 高老，什么是WPC法？是否就是PW法？<br /> <br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <br /> WP是由单色塞特和系数平衡方程组求解镜头镜结构的全过程，而WPC又包括了色差的塞特和系数平衡方程组，因此WPC才应是这种方法的完整全称。<br /> <br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <br /> 附件里只有一个zemax文件，能把讲稿部分也发出来吗？<br /> <br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>如果这样的话，用Matlab应该也能达到同样的效果吧。</P><br /> <br /> <br /> <br /> <br /> </div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>是的，用Matlab应该可以。</P></div> <div class="postmsg">这个结果有点问题啊. 为什么渐晕这么大? 另角度也没有达到60*2? 畸变有考虑吗?</div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>真想去听听高老师的设计思想</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>。。。可是俺没钱。。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>郁闷</P></div> <div class="postmsg">这只是个初始结构，没时间再做下去了。光学同行可以在此基机础上改进。举此例只在说明Methmatica在WPC法上的功能。</div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>感觉不怎么理想啊，弱弱的问一句，线对数是怎么算的，按MTF大于0.2?</P></div> <div class="postmsg">这是一个初解，没时间作下去了。线对数是怎么算的问题可参考“数码镜头设计原理(鉴别率)”<br /> </div> <div class="postmsg"><div class="quote"><blockquote><B>以下是引用<I>GGX19458132</I>在2005-3-9 19:46:27的发言：</B><br /> 这是一个初解，没时间作下去了。线对数是怎么算的问题可参考“数码镜头设计原理(鉴别率)”</blockquote></div><br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>可不可以发给我一份，walk5000@163.com</P></div> <div class="postmsg">为什么OPDX没有按照设置的视场设置那，而特意取了一个0.6666视场。</div> <div class="postmsg">真是好东西啊！！！！！！！！！！</div> <div class="postmsg">挺好的资料阿<br /> <br /> 挺好的<br /> 谢谢昂,~~~~<br /> 简直就是经典</div> <div class="postmsg">謝謝老師的無私分享啊\.....頂喔.......</div> <div class="postmsg">matlab也是可以的，都是非常伟大的软件</div> <div class="postmsg">多谢分享，学习一下mathematics<br /> </div> <div style="height200px;"></div> </div> </div> </div> </div></div> </div> <!--autocomment filter by maxnum--> <div class="ft_wp"> <div id="ft" class=" cl"> <div id="flk" > <p> <a href="http://wpa.qq.com/msgrd?V=3&Uin=20600600&Site=光电工程师社区&Menu=yes&from=discuz" target="_blank" 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