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align="right"><font color="#000066">[此贴子已经被作者于2004-7-22 20:22:55编辑过]</font></div><br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <br /> 比如在MTF里可以看到 线对数/mm,是不是 1/线对数 就代表分辨率的数值<br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>这个你也许可以自己设计一个宏能达到你的要求：</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>就是将MTF求倒数然后再在图上表示出来就可以咯！</P><br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <br /> 我也不太明白, 比如说分辨率为2um的物镜, 可以把2um转换成,线对数. 但是,MTF是在某线对数(空间频率)时的百分比. 百分之多少算可以分辨?<br /> <br /> <br /> <br /> </div> <div class="postmsg"><br /> <br /> 就看你怎么用光学系统啦，如果直接目视，对2um的对应250lp/mm，MTF在该频率处达到0.05以上就可以啦。<img src="static/image/smiley/default/em05.gif" smilieid="34" border="0" alt="" /><img src="static/image/smiley/default/em05.gif" smilieid="34" border="0" alt="" /><br /> <br /> <br /> <br /> </div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>对于一般物镜，分辨率为2μm的提法不是很准确。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>伯爵之光说的对，如果你要分辨2μm的距离，分辨率至少应达到250lp/mm。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>设计物镜前首先应该确定相对孔径，相对孔径越大，理论分辨率越高，否则理论分辨率不够，怎么校正像差都没用。</P></div> <div class="postmsg">目视系统一般要求分辨率要达到多少lp/mm?</div> <div class="postmsg">人眼的分辨率你应该知道的。目视系统的分辨率不应该低于人眼的分辨率。</div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>ABR，什么是相对孔径？不好意思，我是初学，问这么浅陋的问题。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>还有一个问题，如果是用CCD接收图像，分辨率应该怎么算？</P></div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />> 相对孔径是指镜头入瞳直径与焦距之比。我觉得还是好好看看光学书的好，否则我这样解释你也不一定清楚。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>用CCD接收也是一样的，都是要计算出接收器的分辨率。比如CCD一个像素的尺寸为6.3μm，则CCD阵列的最大空间频率可以用两倍的像素大小的倒数来计算，1÷2×0.0063=79.3LP/mm。</P></div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />><B><FONT color=#0000ff>伯爵之光：</FONT></B></P><br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />><FONT color=#0000ff><B> </B></FONT><FONT color=#000000>人眼的分辨率至多50lp/mm</FONT></P><br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />><B><FONT color=#0000ff> 但我看书上说：</FONT></B>视网神经细胞的直径一般取0.006mm，按此计算就是<FONT color=#f70909><B>83.3p/mm</B></FONT></P></div> <div class="postmsg">设在物空间有两个物点，经过眼睛成像在视网膜上。那么这两个像点的距离为多少的时候眼睛分辨不出来呢？这由视神经细胞的直径和眼睛的特性决定。只有当这两个像点成像在相隔的两个视神经细胞上，眼睛才能够分辨出来，成像在相邻的视神经细胞上时，视神经就无法分辨出两个像点。视神经细胞的直径一般为0.001～0.003毫米。因此，黄斑上视网膜能够分辨的最短距离不会大于0.006毫米。由眼睛的焦距还可以计算出眼睛的视角分辨率大约为一分。以上为眼睛观察两个发光点的情形。如果眼睛观察的是两条直线，则视角分辨率可以达到10秒。</div> <div class="postmsg"><DIV class=quote><B>以下是引用<I>伯爵之光</I>在2004-7-9 11:38:52的发言：</B><br /> 就看你怎么用光学系统啦，如果直接目视，对2um的对应250lp/mm，MTF在该频率处达到0.05以上就可以啦。<img src="static/image/smiley/default/em05.gif" smilieid="34" border="0" alt="" /><img src="static/image/smiley/default/em05.gif" smilieid="34" border="0" alt="" /></DIV><br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>MTF 为0.05是不是太小了, 如果做为刻蚀应该达到多少</P></div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>设计物镜前首先应该确定相对孔径，相对孔径越大，理论分辨率越高，否则理论分辨率不够，怎么校正像差都没用。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />><FONT color=#ee3d11><b>ABR,</b></FONT>相对口径和分辨率的具体关系是什么,我只知道和数值孔径NA的关系式,但数值孔径和相对孔径只有物在焦点附近才可以近似相等</P></div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>N=1/1.22λF</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>N-照相系统的分辨率，F-照相物镜的光圈数，也称F数，是相对孔径的倒数。λ-波长。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>数值孔径一般用在显微镜的分辨率上。</P></div> <div class="postmsg">这是瑞利判据，还有其他的判据标准，如1/&micro;F（波长的Lamda怎么输入我不知道啦）<img src="static/image/smiley/default/em05.gif" smilieid="34" border="0" alt="" /></div> <div class="postmsg">光学系统的分辨率要高于CCD或底片的分辨率，浪费点也可以。相对孔径的考虑还需考虑能量。</div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>光学系统分辨率要高于CCD分辨率，因为动态摄影时要降低MTF。</P></div> <div class="postmsg">形不成系统，建议看哪本书较好？？？？？？</div> <div class="postmsg"><b><br /> <DIV class=quote><b>以下是引用<I>伯爵之光</I>在2004-7-9 11:38:52的发言：<br /> </b>就看你怎么用光学系统啦，如果直接目视，对2um的对应250lp/mm，MTF在该频率处达到0.05以上就可以啦。<img src="static/image/smiley/default/em05.gif" smilieid="34" border="0" alt="" /><img src="static/image/smiley/default/em05.gif" smilieid="34" border="0" alt="" /></DIV></b><br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>如果使用CCD接收呢？假定CCD的分辨率很好，那在要求的空间频率处百分之多少算可以分辨？</P></div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>我觉得楼主的问题开始没有写清楚各种条件。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>单纯说分辨率的要求很难能最后确定最终的要求。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>如果把这个项目的各种情况说清楚，这样大家才好提出建议。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>如果因为保密原因，那就算了:)</P></div> <div class="postmsg"><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>我觉得楼主的问题开始没有写清楚各种条件。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>单纯说分辨率的要求很难能最后确定最终的要求。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>如果把这个项目的各种情况说清楚，这样大家才好提出建议。</P><<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>如果因为保密原因，那就算了:)</P></div> <div class="postmsg">其实也没什么好保密的，只是很简单的系统，我已经在一楼上传数据，请帮忙看一下分辨率，敬请告知根据</div> <div class="postmsg"><DIV class=quote><B>以下是引用<I>carfieldbsd</I>在2004-7-21 17:02:19的发言：</B><br /> <br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>我觉得楼主的问题开始没有写清楚各种条件。</P><br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>单纯说分辨率的要求很难能最后确定最终的要求。</P><br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>如果把这个项目的各种情况说清楚，这样大家才好提出建议。</P><br /> <<img src="static/image/smiley/default/titter.gif" smilieid="9" border="0" alt="" />>如果因为保密原因，那就算了:)</P></DIV><br /> <br /> 不守信用</div> <div style="height200px;"></div> </div> </div> </div> </div></div> </div> <!--autocomment last=2025-12-17 09:34:25--> <div class="ft_wp"> <div id="ft" class=" cl"> <div id="flk" > <p> <a href="http://wpa.qq.com/msgrd?V=3&Uin=20600600&Site=光电工程师社区&Menu=yes&from=discuz" target="_blank" title="QQ"><img 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